SUBNETTING

SUBNETTING CALCULATION

For this calculation we use class B address.

172.16.0.0

There are 5 faculties and 1 IT Centre. Thus, we have a total of 6 subnets.

First, we need to find the total number of possible subnets using the formula 2^n, where n equals the number of host bits borrowed. We want 8 possible subnets since it is more than 6 which are our total subnets. That is mean by using the formula:

No. of subnet per network: 2^3 = 8

The number of hosts bits borrowed are 3.

For class B, 1st and 2nd octet represents netid. Number of 1s in the 3rd octet shows how many bits were borrowed from the hostid for subnetting.

Thus, the subnet mask is 11111111.11111111.11100000.00000000 or 255.255.224.0

From the subnet mask we can get the

No. of hosts in a subnet: 2^13 - 2 = 8190

Block size of one subnet: 256 - 224 = 32.0

Therefore,

By referring to the table above, the 5th subnet is assigned to the IT Centre while the 5th subnet and the 5th available address in the subnet are assigned to Ulearn System Server. Thus, the IP address for Ulearn System Server is 172.16.160.5/19.